以下程式執行後，mystery_len 會是多少？ A = [2, 3, 2, 3, 1, 3, 3, 3, 2, 2, 2, 2, 1, 1] n = len
Amystery_len = 1 curr_len = 1 for i in range(1, n): if A[i] == A[i - 1]: curr_len += 1 else: if curr_len > mystery_len: mystery_len = curr_len curr_len = 1 if curr_len > mystery_len: mystery_len = curr_len
B3
C4正確答案
D7
答案與詳解
