ΔHf°為生成熱，已知 SbCl₃(g) 的ΔHf° = -313.8 kJ/mol，Sb(g)的ΔHf° = 262.3 kJ/mol，Cl(g) 的ΔHf° = 121.7 kJ/mol，請問 Sb－Cl 的平均鍵能約為：
A104.6 kJ/mol
B262.3 kJ/mol
C313.7 kJ/mol正確答案
D121.7 kJ/mol
答案與詳解
為什麼答案是 C
正確計算：總鍵能 = ΔHf°[Sb(g)] + 3×ΔHf°[Cl(g)] − ΔHf°[SbCl₃(g)] = 262.3 + 3×121.7 − (−313.8) = 262.3 + 365.1 + 313.8 = 941.2 kJ；平均鍵能 = 941.2 ÷ 3 ≈ 313.7 kJ/mol。
考點：漏計原子化能考點：數字混淆考點：Hess定律鍵能
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