矩陣 A = \begin{bmatrix}-1&0&0&0\\8&1&0&0\\4&-8&1&0\\5&-4&8&-1\end{bmatrix} 而矩陣 B = \begin{bmatrix}-1&1&-1&-3\\0&2&2&-1\\0&0&-3&1\\0&0&0&4\end{bmatrix}，則此二矩陣的乘積 AB 之行列式值（Determinant）為何？
Adet(AB) = 24正確答案
Bdet(AB) = -24
Cdet(AB) = 12
Ddet(AB) = -12
答案與詳解
