有兩個電流方程式分別為 i1(t)=10sin(120πt) A，i2(t)=5sin(120πt+30°) A，則此兩波形時間差為何？
A2.51ms
B1.02ms
C1.39ms正確答案
D1.53ms
答案與詳解
為什麼答案是 C
Δt = 30°/(360°×60Hz) = 30/(360×60) = 1/720 s ≈ 1.389ms ≈ 1.39ms，完全正確
考點：相位差時間換算
載入中…
Δt = 30°/(360°×60Hz) = 30/(360×60) = 1/720 s ≈ 1.389ms ≈ 1.39ms，完全正確
