圖示為一加偏壓之非反相施密特觸發器,電路中 OPA 之輸出飽和電壓為±15 V,則其遲滯電壓(hysteresis voltage)VH 為何?

A3.75 V
B5 V
C7.5 V
D10 V正確答案
答案與詳解

正確答案。由圖:R1=50kΩ(輸入端到正相端節點),R2=150kΩ(正相端節點到輸出端),VR=+2V接反相端。正相輸入端電壓V+ = Vs與Vo透過R1、R2分壓決定。觸發閾值由V+=VR=2V求得:當Vo=+15V時,UTP = VR − (Vo−VR)×(R1/R2) 計算如下:V+ = (R2×Vs + R1×Vo)/(R1+R2),令V+=2V,UTP(Vs) = 2×(R1+R2)/R2 − Vo×(R1/R2) = 2×(200/150) − 15×(50/150) = 2.667 − 5 = −2.333...,實際用另一公式:V+_node = Vo×[R1/(R1+R2)] + Vs×[R2/(R1+R2)],令等於2V求Vs觸發點:當Vo=+15V,UTP= [2×(R1+R2) − Vo×R1]/R2 = [2×200k − 15×50k]/150k = [400k−750k]/150k = −350k/150k ≈ −2.33V;當Vo=−15V,LTP= [2×200k −(−15)×50k]/150k = [400k+750k]/150k = 1150k/150k ≈ 7.67V。VH = LTP − UTP = 7.67−(−2.33) = 10V。
