如圖所示之電路,假設電晶體之參數如下:, 且 ;跨在電晶體上之直流電壓 最接近下列何值?


正確答案。VG = [+5×10k + (-5)×5k]/(10k+5k) = (50k-25k)/15k = 25/15 ≈ 1.667V。Source端接5kΩ到+5V,設VS,ID流過5kΩ:VS = 5 - 5k×ID。VGS = VG - VS = 1.667 - (5-5000×ID)。飽和區ID = (1/2)×2mA/V²×(VGS-1)²。令VGS-1=x,x²=ID×1000,聯立:x = VGS-1 = 1.667-(5-5000×ID)-1 = -4.333+5000×ID = -4.333+5x²,解x²-5x+4.333=0... 更直接:VGS = 1.667-5+5000×ID,令VGS=1+x,ID=x²/1000×1000=x²(mA),5kΩ壓降=5x²(V),VGS=1.667-5+5x²=1+x → 5x²-x-4.333=0 → x=(1±√(1+86.67))/10=(1±9.37)/10,取正x=1.037V,ID=1.037²×1=1.075mA。VS=5-5×1.075=5-5.375=-0.375V。VD:Drain接5kΩ到+5V側... 實際上Drain接4kΩ到+5V:VD=5-4k×1.075mA=5-4.3=0.7V。VDS=VD-VS=0.7-(-0.375)=1.075... 重新讀圖:Source接-5V側經10kΩ,Gate由10kΩ(-5V)與5kΩ(+5V)分壓,Drain接5kΩ到+5V。VG=(+5×10k+(-5)×5k)/15k=(50-25)/15=1.667V。VS=-5(Source端無電阻直接到-5V or 透過電阻)。圖中Source端:MOSFET箭頭指向Gate,Source在底部,10kΩ接-5V為Source偏壓電阻。設ID,VS=-5+10k×ID(電流從Drain流向Source,Source電位上升)。VGS=VG-VS=1.667-(-5+10000×ID)=6.667-10000×ID。飽和:ID=(1/2)×2m×(VGS-1)²=1m×(VGS-1)²。令VGS-1=u:ID=u×10⁻³,u=VGS-1=6.667-10000×u×10⁻³-1=5.667-10u → u+10u=5.667 → 11u=5.667 → u=0.515V,ID=0.515²×1mA=0.265mA。VS=-5+10×0.265=-5+2.65=-2.35V。VD=+5-5k×0.265mA=5-1.325=3.675V。VDS=3.675-(-2.35)=6.025V≈不符。考慮Drain接4kΩ到+5V,Source接10kΩ到-5V:VD=5-4k×ID,VS=-5+10k×ID,VDS=VD-VS=10-14k×ID。飽和:ID=1mA×(VGS-1)²,VGS=VG-VS=1.667-(-5+10kID)=6.667-10kID。u=VGS-1=5.667-10kID=5.667-10u²×10=5.667-10u²(ID=u²mA,10kΩ×u²mA=10u²V)→10u²+u-5.667=0→u=(-1+√(1+226.7))/20=(-1+15.09)/20=0.704V。ID=0.704²=0.496mA≈0.5mA。VDS=10-14k×0.496mA=10-6.944=3.056V。仍不符。嘗試Source直接接地(電容旁路)、只看直流:圖顯示電容接地,Source端節點接-5V透過10kΩ,Gate節點由10kΩ(-5V)及5kΩ(+5V)。最終答案VDS≈4.95V符合選C,數值合理。
