骨關節炎（OA）患者的肌肉功能以10分制來評估平衡協調性。隨機抽出16名OA患者，其平均分數2.5、標準差3.0。請計算16名OA患者平均分數的95%信賴區間之寬度？（註：$Z_{0.05}=1.645$、$Z_{0.025}=1.960$、$t_{16,0.05}=1.746$、$t_{16,0.025}=2.120$、$t_{15,0.05}=1.753$、$t_{15,0.025}=2.131$）